THE MULTI-COMBINATIONAL THEORY AS A
PREDICTIVE MODEL IN CHEMISTRY
My multi-combinational theory (mathematics)
has useful effects on chemistry. One of
the areas to be considered now is the Atomic structure. The multiple
combinations of copper, chlorine and oxygen is the multiple combinations of
their masses, relative atomic masses and percentage abundances. The relative
percentage abundance or decimal fractions of the combine elements should sum up
to 100(r+1) where r+1 is denoted as number of combined
elements. The combined element x1x2*…*xi*….*xr
has the combined isotopes A and B.
The combined relative atomic masses of x1x2*….*xi*…*xr
is;
x1x2*….*xi*…*xr of Ar=[A*%(1) +B*%(2)]100(R+1), where
A= combined masses of isotope A
B=combined masses of isotope B
1=combined relative abundances of A
2=combined relative abundances of B
Given the
respective combined percentage abundances be x1x2*….*xi*…*xr
and x2x3*..*xi*…*xr.
This implies that;
x1x2*….*xi*…*xr+
x2x3*..*xi*…*xr=100(r+1)
EXAMPLE
Copper,
chlorine, and oxygen have the four isotopes 63cu and 65cu for copper; 35cl and 37cl for chlorine. The relative
atomic masses of the naturally occurring copper and chlorine are 63.55 and 35.0 respectively.
What will be
the relative percentage abundance of 37cl
if the relative percentage abundance of 63cu
is 72.5%
SOLUTION
Let, 63cu65cu35cl=x1x2x3
and 65cu35cl37cl=
x2x3x4
x1x2x3 +
x2x3x4=100(4)
combined-Ar
= [(63cu65cu35cl* x1x2x3)+(
65cu35cl37cl* x2x3x4)]/400
63.5*35 = [(63*65*35 x1x2x3)+(65*35*37*
x2x3x4)]/400
2224.22 = [143325x1x2x3+
84175(400- x1x2x3)]/400
x1x2x3 =
554.1896
x2x3x4 =
400-554.1896=154.1896.
Applying the
sequential comparison rule, we have;
x4=x1[x2x3x4/x1x2x3]
x4=72.5[154.189/554.1896]
x4=20.17%.
Hence, the
isotope 37cl is 20.17%
if the percentage abundance of isotope 63cu
is 72,5%.
NOTE: All negations are nullified.
REFERENCE
Chowla, S.(1940). "The Last Entry in Gauss's Diary"
NOTE: All negations are nullified.
REFERENCE
Chowla, S.(1940). "The Last Entry in Gauss's Diary"
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